Yet again, Cher has driven fans wild with anticipation for whatever she is to do next, this time by posting a taste of a new song off her forthcoming ABBA cover album, which leads me to believe this ...
Stereogum: Sabrina Carpenter Stops Doing Custom “Nonsense” Outros But Brings Comedy Bits, ABBA Cover To Tour Opener
Sabrina Carpenter Stops Doing Custom “Nonsense” Outros But Brings Comedy Bits, ABBA Cover To Tour Opener
Iconic supergroup ABBA is reuniting for the first time since splitting up in 1982. ABBA announced a new upcoming album on Instagram on Thursday. The new album Voyage is due to be released Nov. 5. ABBA ...
That is, there seems to be fairly strong symbolic evidence that for $n=4$, if $ABBA-BAAB = A-B$ and $A$ is nilpotent, then $B^4 = \lambda I$ for some $\lambda$.
Because abab is the same as aabb. I was how to solve these problems with the blank slot method, i.e. _ _ _ _. If I do this manually, it's clear to me the answer is 6, aabb abab abba baba bbaa baab Which is the same as $$\binom {4} {2}$$ But I don't really understand why this is true? How is this supposed to be done without brute forcing the ...
Hint: in digits the number is $abba$ with $2 (a+b)$ divisible by $3$.
Although both belong to a much broad combination of N=2 and n=4 (AAAA, ABBA, BBBB...), where order matters and repetition is allowed, both can be rearranged in different ways: First one: AABB, BBAA,