Bond House

It is not as if BNP Paribas came from nowhere to become IFR’s Euro Bond House for 2008. It has been an ever-present force in the market sector, plying its trade throughout the years across good times ...

Yahoo: 200 Years of Christmas at the Historic Col. William Bond House

The only proper way to do it ab initio is to calculate the energy (E) for various internuclear distances (R) and then to approximate the equilibrium bond length by choosing the distance which has the lowest energy, or by fitting the E (R) points to something like a Morse potential (which is decent for short-distances), Lennard-Jones potential (which is decent for large distances), or the one ...

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If you know the bond lengths of few such compounds, you can derive a very accurate linear correlation between the bond length and the frequency. So while you can't directly predict bond lengths from IR alone, you can likely develop a correlation between a particular IR frequency and bond length for a series of related compounds.

HI @Magic_Number, after running with more recorded timestep, I think the main reason is because the molecule pass through zlo and have atom deleted, as result, the bond connecting that atom is lost. But I know having a fixed z boundary is possible to run because that's what I found from several lammps papers.

I need some cutoff radii to count bonds between different atoms in my system. When a .cif file is opened in Vesta, there are some default values of min and max bond lengths between two atomic speci...

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5 If your desire is to get the best bond length from that website, then I would begin by looking for the largest basis set (in this case it's aug-cc-pVQZ) and the method that is expected to recover the most correlation energy (in this case it's CCSD (T)=FULL), so the CCSD (T)=FULL/aug-cc-pVQZ bond length of 1.540 Å is a good starting point.

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