What's actually the difference between String[] and String... if any? The convention is to use String[] as the main method parameter, but using String... works too, since when you use varargs you can call the method in the same way you call a method with an array as parameter and the parameter itself will be an array inside the method body.
What does $ {} (dollar sign and curly braces) mean in a string in JavaScript? Asked 10 years, 1 month ago Modified 2 years, 4 months ago Viewed 431k times
What does ${} (dollar sign and curly braces) mean in a string in ...
9 I believe you just migrated from C++, Well in java you have to initialize a data type (other then primitive types and String is not a considered as a primitive type in java ) to use them as according to their specifications if you don't then its just like an empty reference variable (much like a pointer in the context of C++).
String array=new String[]; String array=new String[]{}; The first won't compile for two reasons while the second won't compile for one reason. The common reason is that the type of the variable array has to be an array type: String[] not just String. Ignoring that (probably just a typo) the difference is:
difference between new String [] {} and new String [] in java
Use the string.equals(Object other) function to compare strings, not the == operator. The function checks the actual contents of the string, the == operator checks whether the references to the objects are equal. Note that string constants are usually "interned" such that two constants with the same value can actually be compared with ==, but it's better not to rely on that.